Question

The grades on a geometry midterm at Springer are roughly symmetric with μ = 73 and σ = 3.0. Umaima scored 72 on the exam. Find the z-score for Umaima's exam grade. Round to two decimal___________.

Answer 1

The z-score for Umaima's exam grade of 72 is approximately -0.33.

Step-by-step explanation:

To find the z-score for Umaima's exam grade, we can use the formula: z = (x - μ) / σ, where x is the exam grade, μ is the mean, and σ is the standard deviation. In this case, Umaima's exam grade is 72, the mean is 73, and the standard deviation is 3. Plugging these values into the formula, we get: z = (72 - 73) / 3 = -0.33. Therefore, the z-score for Umaima's exam grade is approximately -0.33.