Final answer:
The z-score for a data value of 109 in a normal distribution with a mean of 98 and a standard deviation of 6 is approximately 1.83.
Step-by-step explanation:
A normal distribution with a mean of 98 and a standard deviation of 6 is given. We need to find the z-score for a data value of 109.
The formula to calculate the z-score is: z = (x - μ) / σ, where x is the data value, μ is the mean, and σ is the standard deviation.
Plugging in the values, we have z = (109 - 98) / 6 = 1.83.
Therefore, the z-score for a data value of 109 is approximately 1.83 (rounded to two decimal places).