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A normal distribution has a mean of 98 and a standard deviation of 6. Find the z-score for a data value of 109. Round to two decimal places.

User Shahar
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Final answer:

The z-score for a data value of 109 in a normal distribution with a mean of 98 and a standard deviation of 6 is approximately 1.83.

Step-by-step explanation:

A normal distribution with a mean of 98 and a standard deviation of 6 is given. We need to find the z-score for a data value of 109.

The formula to calculate the z-score is: z = (x - μ) / σ, where x is the data value, μ is the mean, and σ is the standard deviation.

Plugging in the values, we have z = (109 - 98) / 6 = 1.83.

Therefore, the z-score for a data value of 109 is approximately 1.83 (rounded to two decimal places).

User Thejaka Maldeniya
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