Question

Three factories produce light globes to supply the market. Factory A produces 20%, while 50% of the globes are produced in factory B and 30% in factory C.2% of the globes produced in factory A, 1% of the globes produced in factory B and 3% of the globes produced in factory C are defective. A globe is selected at random in the market

What is the probability that the globe is defective? a. 0.264 b. 0.060 C. 0.018 d. 0.333
a. 0.222 Given that the globe is defective, what is the probability that Factory A produced it? b. 0.040 C. 0.256 d. 0.877
a. 0.278 What is probability, given that the globe is defective, that Factory C produced it? b. 0.050 c.0.500 d. 0.778

Answer 1

To find the probability that a globe selected at random is defective, we need to consider the percentages of globes produced by each factory and the percentages of defective globes produced by each factory. Therefore, the probability that a globe selected at random is defective is 0.018.

Step-by-step explanation:

To find the probability that a globe selected at random is defective, we need to consider the percentages of globes produced by each factory and the percentages of defective globes produced by each factory.

Factory A produces 20% of the globes, of which 2% are defective. Factory B produces 50% of the globes, of which 1% are defective. Factory C produces 30% of the globes, of which 3% are defective.

To find the overall probability of a globe being defective, we can multiply the probabilities of each factory producing a defective globe by the percentage of globes produced by that factory:

P(defective) = (20% * 2%) + (50% * 1%) + (30% * 3%) = 0.4% + 0.5% + 0.9% = 1.8%

Therefore, the probability that a globe selected at random is defective is 0.018.