Question

Assume a normal distribution in the distance traveled per car. The mean = 100 miles and the standard deviation =10 miles. How many miles will be traveled by at least 90% of the cars? 912 1225 87.2 112.8 QUESTION 6 In a lelt-skewed distribution the third quartile is farther away from the median than the first quartile the first quartile is farther away from the median than the third quartile in excess of 66% of the items lie from the first quartile to the third quartile the moan is greater than the median Of the following, which is true?

Answer 1

At least 90% of the cars will travel within two standard deviations, which is 100 +/- 20 miles.

Step-by-step explanation:

In a normal distribution with a mean of 100 miles and a standard deviation of 10 miles, we can use the empirical rule to determine how many miles will be traveled by at least 90% of the cars.

1. 
   
2. Within one standard deviation of the mean (100 ± 10 miles), we have approximately 68% of the cars.
3. 
   
4. Within two standard deviations (100 ± 20 miles), we have approximately 95% of the cars.
5. 
   
6. Within three standard deviations (100 ± 30 miles), we have more than 99% of the cars.

Therefore, at least 90% of the cars will travel within two standard deviations, which is 100 ± 20 miles. So, the answer is 80 miles to 120 miles.