Question

Lot x be s normelly distributed continuous random varable with a mean of 297 and a standard deviation of 19. Delermine the value of x such that the area to the right of x is 0.9834 . Round the solution to two becimel places, if necessary.

Answer 1

To find the value of x such that the area to the right of x is 0.9834 in a normal distribution with a mean of 297 and a standard deviation of 19, we can use the z-score formula to solve for x. After substituting the values into the formula and solving, we find that x = 340.27.

Step-by-step explanation:

To find the value of x such that the area to the right of x is 0.9834 in a normal distribution with a mean of 297 and a standard deviation of 19, we need to use the standard normal distribution and the z-score formula.

The z-score corresponding to an area of 0.9834 to the left is approximately 2.33. We can substitute this value into the z-score formula as follows:

z = (x - mean) / standard deviation

2.33 = (x - 297) / 19

Solving for x, we get:

x = 2.33 * 19 + 297 = 340.27

Rounding to two decimal places, we find that x = 340.27.