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Construct the confidence interval for the population mean mu c=0.95, bar{x}=15.4, sigma=9.0 ext {, and } n=40 A 95% confidence interval for mu is 1

User Iluwatar
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Final answer:

To construct a 95% confidence interval for a population mean with a known standard deviation, use the formula (x - EBM, x + EBM), where x is the sample mean, and EBM is the error bound calculated using the Z-value for the desired confidence level. In the provided example, the 95% confidence interval for the population mean is (12.63, 18.17).

Step-by-step explanation:

Constructing a 95% Confidence Interval for the Population Mean

To construct a 95% confidence interval for the population mean μ when the population standard deviation σ is known, and we have a sample mean μ, the formula is (x − EBM, x + EBM), where x is the sample mean and EBM is the error bound for the mean. The error bound can be calculated using the standard normal distribution (Z-distribution) because the population standard deviation is known.

Let's consider the provided example:

  • Sample mean (μ) = 15.4
  • Population standard deviation (σ) = 9.0
  • Sample size (n) = 40
  • Confidence level (C) = 95%

Firstly, we need to find the Z-value that corresponds to the 95% confidence level. Since the normal distribution is symmetrical, we look for the Z-value that leaves 2.5% in the tail, which is approximately 1.96. Next, we calculate the error bound using the formula:

EBM = Z * (σ / √ n)

Substituting the values we get:

EBM = 1.96 * (9 / √ 40) = 1.96 * (9 / 6.32) ≈ 2.77

Therefore, the confidence interval is:

(15.4 - 2.77, 15.4 + 2.77) = (12.63, 18.17)

We can say with 95% confidence that the true population mean lies within the interval (12.63, 18.17).

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