Final answer:
To construct the 90% confidence interval for n=170 and ˆp=0.74, we use the formula CI = ˆp ± z * sqrt(ˆp(1-ˆp)/n).
Step-by-step explanation:
To construct a 90% confidence interval when n = 170 and ˆp (p-hat) = 0.74, we can use the formula:
CI = ˆp ± z * sqrt(ˆp(1-ˆp)/n),
Where ˆp is the sample proportion, z is the z-score corresponding to the desired level of confidence, and n is the sample size.
Substituting in the given values, we have:
CI = 0.74 ± 1.645 * sqrt(0.74 * (1 - 0.74) / 170)
Calculating this, we get:
CI = 0.74 ± 0.064
Therefore, the 90% confidence interval is (0.676, 0.804).