Question

Psychologists often measure how long it takes mice to find their way through a maze. The times for one particular maze follow an approximately Normal distribution with mean 18 seconds and standard deviation 3 seconds. A researcher thinks that a loud noise will cause mice to complete the maze faster (in less time), but not change the standard deviation. She uses a loud noise to stimulate each of 10 mice right before she measures how long it takes each of them to complete the maze. The sample mean time is x = 16.2 seconds.what is the value of the one-sample z test statistic for this example?

Answer 1

The value of the one-sample z test statistic for the given example is -1.896.

Step-by-step explanation:

The value of the one-sample z test statistic can be calculated using the formula:

z = (x - μ) / (σ / √n)

where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

In this case, x = 16.2 seconds, μ = 18 seconds, σ = 3 seconds, and n = 10 mice.

Substituting these values into the formula, we get:

z = (16.2 - 18) / (3 / √10) = -1.8 / 0.9487 = -1.896

Therefore, the value of the one-sample z test statistic for this example is -1.896.