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If n=570 and ˆp (p-hat) = 0.34, construct a 99% confidence

interval. Give your answers to three decimals.

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Final answer:

To construct a 99% confidence interval given n = 570 and p-hat = 0.34, use the formula CI = p-hat ± Z * sqrt((p-hat * (1-p-hat)) / n). Determine the critical value Z associated with a 99% confidence level and calculate the confidence interval. The resulting interval is (0.297, 0.383).

Step-by-step explanation:

To construct a 99% confidence interval, we will use the formula:

CI = p-hat ± Z * sqrt((p-hat * (1-p-hat)) / n)

Substituting in the given values: n = 570 and p-hat = 0.34, we can calculate the confidence interval:

CI = 0.34 ± Z * sqrt((0.34 * (1-0.34)) / 570)

To find the value of Z, we need to determine the critical value associated with a 99% confidence level. Looking up the value in a standard normal distribution table, Z ≈ 2.576.

Plugging in this value and completing the calculation, we get:

CI ≈ 0.34 ± 2.576 * sqrt((0.34 * (1-0.34)) / 570)

CI ≈ 0.34 ± 0.043

Therefore, the confidence interval is approximately (0.297, 0.383).

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