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The probability of a child having Down Syndrome is .01 for a woman who conceives at age 40.A first trimester test for Down Syndrome involving ultrasound has a 5% false positive rate. The test is 85% accurate in correctly identifying Down Syndrome when the baby actually h as Down Syndrome. a. Constructa 2-way table assuming a study of this screening test involves 2000 subjects. b. Find P

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Final answer:

To answer the student's question, a two-way table was constructed based on the given probabilities, and the probability of a positive test result was calculated to be 0.058 or 5.8% when assuming a study of 2000 subjects.

Step-by-step explanation:

The question involves constructing a two-way table and calculating the probability related to the screening of Down syndrome for women who conceive at age 40. Given that the probability of a child having Down syndrome is 0.01 for a woman at age 40, and a first trimester test for Down syndrome has a 5% false positive rate and is 85% accurate in identifying Down syndrome when it is actually present, we can create a two-way table with these probabilities based on a study involving 2000 subjects.

Constructing the Two-Way Table

First, we must calculate the expected numbers:

  • Number of children with Down syndrome: 0.01 × 2000 = 20
  • Number of children without Down syndrome: (1 - 0.01) × 2000 = 1980

From the 20 children with Down syndrome, the test is expected to correctly identify 85% of them, so:

  • True positives: 0.85 × 20 = 17
  • False negatives (15% missed): 0.15 × 20 = 3

Out of the 1980 without the condition, 5% will have a false positive:

  • False positives: 0.05 × 1980 = 99
  • True negatives: 1980 - 99 = 1881

Now we can present this data in a two-way table:

Down SyndromeNo Down SyndromePositive Test1799Negative Test31881

Probability Calculation

To find the probability of a positive test result P(Positive), we add the true positives to the false positives and divide by the total number of subjects:

P(Positive) = (True Positives + False Positives) / Total Subjects

P(Positive) = (17 + 99) / 2000

P(Positive) = 116 / 2000 = 0.058

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