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Its your answer as a fraction reduction of y²+11y+28=0

User Bobblez
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Final answer:

The quadratic equation y² + 11y + 28 = 0 can be factored into (y + 7)(y + 4) = 0, and its solutions are y = -7 and y = -4.

Step-by-step explanation:

The quadratic equation given is y² + 11y + 28 = 0. To find the solution to this equation, we can factor it into (y + 7)(y + 4) = 0, setting each factor equal to zero. Therefore, the solutions to the equation are y = -7 and y = -4, which are the points where the parabola crosses the y-axis.

User Atsuko
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