Final answer:
The rms current of the 20.0Ω resistor with an AC source of V(t) = (170V)sin(60t) is approximately 6 A, the maximum current is 8.5 A, and the power delivered is approximately 723 W.
Step-by-step explanation:
The question asks to calculate the root mean square (rms) and maximum values of the current in a resistor, as well as the power delivered to it, when an AC source with a specific voltage function is applied across it. Using the formula I(t) = V(t) / R, where I(t) is the instantaneous current, V(t) is the given voltage function, and R is the resistance, we can find the maximum current by taking the peak voltage and dividing it by the resistance. Given that V(t) = (170V)sin(60t), the maximum current (Imax) in the 20.0Ω resistor is 8.5 A (170V / 20Ω). The rms current is then this value divided by the square root of two, which is approximately 6 A. Finally, the power delivered to the resistor can be calculated using P = Irms^2 * R, resulting in approximately 723 W.