Question

A flat circular coil of radius 5.90 cm and exactly 28 loops is rotated in a magnetic field of magnitude 1.31 T. What is the minimum angular velocity at which the coil can be rotated to achieve an EMF of 122 V on the coil?

Answer 1

To calculate the minimum angular velocity at which the coil can be rotated to achieve an EMF of 122 V, use the formula EMF = N * B * A * ω, where N is the number of loops, B is the magnetic field strength, A is the area of the coil, and ω is the angular velocity.

Step-by-step explanation:

In order to calculate the minimum angular velocity at which the coil can be rotated to achieve an EMF of 122 V on the coil, we can use the formula:

EMF = N * B * A * ω Where EMF is the electromotive force, N is the number of loops in the coil, B is the magnetic field strength, A is the area of the coil, and ω is the angular velocity. Plugging in the given values: EMF = 122 V N = 28 B = 1.31 T A = π * r^2 = π * (0.059 m)^2 Solving for ω, we get: ω = EMF / (N * B * A) = 122 V / (28 * 1.31 T * π * (0.059 m)^2) Calculating this value will give us the minimum angular velocity required to achieve the desired EMF.