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A hollow, spherical shell with a mass of 2.00 kg rolls without slipping down a 30.0 ∘ slope. Find the acceleration.

Express your answer with the appropriate units.

User Wyc
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Final answer:

To find the acceleration of the hollow, spherical shell rolling down the slope, we use the equation: acceleration = (mass * gravity * sin(angle)) / (mass * radius). The acceleration is approximately 4.9 m/s^2.

Step-by-step explanation:

First, we need to find the linear acceleration of the hollow, spherical shell rolling down the slope. We can use the equation:

acceleration = (mass * gravity * sin(angle)) / (mass * radius)

Plugging in the given values, we get:

acceleration = (2.00 kg * 9.8 m/s^2 * sin(30.0°)) / (2.00 kg)

Simplifying this equation, we find that the acceleration is approximately 4.9 m/s^2.

User Swampsjohn
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