Question

An optician is designing a contact lens. The material has is an index of refraction of 1.45 . In order to yield the prescribed focal length, the optician specifies the following dimensions: - inner radius of curvature =+2.48 cm - outer radius of curvature =+1.96 cm where the inner radius of curvature describes the surface that touches the eye, and the outer radius of curvature describes the surface that first interacts with incoming light. What is the focal length of this contact lens (in cm )? cm

Answer 1

The focal length of the contact lens is approximately -1.94 cm.

Step-by-step explanation:

The focal length of a contact lens can be determined using the lens maker's equation, which is 1/f = (n - 1)((1/R1) - (1/R2)), where f is the focal length, n is the refractive index of the lens material, R1 is the radius of curvature of the inner surface, and R2 is the radius of curvature of the outer surface.

In this case, the refractive index of the lens material is given as 1.45. The inner radius of curvature is +2.48 cm and the outer radius of curvature is +1.96 cm.

Plugging these values into the lens maker's equation:

1/f = (1.45 - 1)((1/2.48) - (1/1.96))

Solving for f, we find that the focal length of the contact lens is approximately -1.94 cm.