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At an energy of 1.12 × 10 ⁻¹⁴ J, what is the velocity of the electrons?

User UmYeah
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Final answer:

The velocity of the electrons at an energy of 1.12 × 10⁻¹⁴ J is 1.62 × 10³ m/s.

Step-by-step explanation:

The velocity of the electrons can be calculated using the formula:

velocity = sqrt((2 * energy) / (mass * c^2))

where energy is the given value of 1.12 × 10⁻¹⁴ J and c is the speed of light, approximately 3 × 10^8 m/s. The mass of an electron is approximately 9.11 × 10⁻³¹ kg.

Substituting the values, the velocity of the electrons is calculated as:

velocity = sqrt((2 * 1.12 × 10⁻¹⁴ J) / (9.11 × 10⁻³¹ kg * (3 × 10^8 m/s)^2))

velocity = 1.62 × 10³ m/s

User Yorimar
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