Final answer:
The heat absorbed from the climber's body to heat snow from -15°C to 37°C includes the heat required to warm the ice, melt it, and then warm the water. For the stove scenario, only the warming of the already melted water needs to be considered. The energy expenditure is significant in the first case.
Step-by-step explanation:
We need to calculate the energy absorbed by a climber's body under two scenarios:
- Heating snow from -15°C to 37°C.
- Melting snow using a stove and then warming it from 2°C to 37°C.
For the first part of the question, we will not use the provided data as it contains a typo (-5.0°C instead of -15°C). The correct process is to calculate the heat required to warm the ice from -15°C to 0°C, the heat of fusion to melt the ice into water, and the heat required to warm the water from 0°C to 37°C. The specific heat capacities (ice and water) and the latent heat of fusion will be required for these calculations.
For the second part, when the climber uses a stove, we only need to calculate the heat required to warm the water (which is already melted by the stove) from 2°C to 37°C using the specific heat of water.
We should note that consuming snow at -15°C would require significant energy expenditure by the climber's body to warm it to body temperature, hence the survival guide's recommendation against doing so.