Question

An electron and a proton are separated by a distance of 2.500⁻¹⁰ m. Based on the above information, the electrostatic force of attraction befween the electron and the proton is:

a. 2.30+10⁻¹⁰ N
b. 5.75 N
c. 3.68⋅10⁻⁹ N
d. 9.21=10⁻¹⁹ N

Answer 1

The electrostatic force of attraction between an electron and a proton is approximately 2.30 x 10^-10 N.

Step-by-step explanation:

The electrostatic force of attraction between an electron and a proton can be calculated using Coulomb's law. The formula for the electrostatic force is F = k * (q1 * q2) / r^2, where F is the force, k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the electron and proton (1.6 x 10^-19 C), and r is the distance between them (2.5 x 10^-10 m).

Plugging in the values into the formula, we get:

F = (8.99 x 10^9 Nm^2/C^2) * (1.6 x 10^-19 C * 1.6 x 10^-19 C) / (2.5 x 10^-10 m)^2 = 2.30 x 10^-10 N

Therefore, the electrostatic force of attraction between the electron and proton is approximately 2.30 x 10^-10 N.