Final answer:
The image location is 23.0 cm from the lens, the magnification is -1, indicating the image is the same size as the object and inverted, and the image height is -5.00 cm, meaning the image is 5.00 cm tall and also inverted.
Step-by-step explanation:
To determine the image location, magnification, and image height for an object in front of a converging lens, we use the lens formula and magnification equation. Here, an object of height 5.00 cm is placed 23.0 cm to the left of a converging lens with focal length 11.5 cm.
The lens formula is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance. Plugging the values in:
1/11.5 cm = 1/23.0 cm + 1/di
After solving, we get:
di = 23.0 cm
Magnification (m) is given by the equation m = - di/do = hi/h, where hi is the image height and h is the object height.
Substituting the known values:
m = - 23.0 cm / 23.0 cm = -1
This implies that the image is the same size as the object but inverted, as indicated by the negative sign.
hi = m * h
hi = -1 * 5.00 cm
Therefore, hi = -5.00 cm, meaning the image is 5.00 cm tall and inverted.