Final answer:
The probability that Jinita is chosen first and Pam is chosen second is 1/36 or approximately 0.0278.
Step-by-step explanation:
To calculate the probability that Jinita is the first person chosen and Pam is the second, we need to consider the total number of possible outcomes and the number of favorable outcomes.
There are 9 students in the class, so the total number of possible outcomes is 9 choose 2, which is equal to 36.
Since we want Jinita to be chosen first and Pam to be chosen second, there is only 1 favorable outcome.
Therefore, the probability is 1/36 or approximately 0.0278.