Final answer:
To give a 0.50 kg newspaper a velocity of 3.0 m/s, it must be thrown with an impulse of 1.5 kg·m/s, calculated using the formula for impulse which is the product of mass and change in velocity.
Step-by-step explanation:
The question asks about the impulse required to throw a 0.50 kg newspaper to give it a velocity of 3.0 m/s. In physics, impulse is defined as the change in momentum of an object, and it is calculated by multiplying the mass (m) of the object by the change in velocity (Δv). Therefore, to find the impulse (J), we use the formula: J = m * Δv. Since the initial velocity (Vi) is zero (assuming the newspaper starts from rest) and the final velocity (Vf) is 3.0 m/s, the change in velocity is simply 3.0 m/s. Substituting the known values into the equation:
J = (0.50 kg) * (3.0 m/s - 0 m/s) = 1.5 kg·m/s.
Therefore, the impulse required to throw the newspaper is 1.5 kg·m/s.