Question

What is the size of the image produced by a converging lens with a focal length of [insert focal length] when an object is placed 34.0 cm behind the lens? Provide the magnification and whether the image is larger or smaller than the actual size.

Answer 1

To determine the size of the image produced by a converging lens, the lens formula 1/f = 1/do + 1/di is used along with the magnification formula m = -di/do. The sign of the magnification indicates if the image is real and inverted, and its absolute value tells us if the image is larger or smaller than the object. The provided object distance is 34.0 cm, but the focal length is needed to complete the calculations.

Step-by-step explanation:

To find the size of the image produced by a converging lens and whether it is larger or smaller than the actual object, we use the lens formula and magnification formula.

However, the focal length (f) is missing in your question, so I cannot provide you with numerical answers. If you can provide the focal length, I can offer a specific solution.

Step 1: Use the lens formula, which is 1/f = 1/do + 1/di, where 'f' stands for focal length, 'do' is the distance of the object from the lens, and 'di' is the distance of the image from the lens. With 'do' given as 34.0 cm, we would plug in the known values along with the given 'f' to find 'di'.

Step 2: Once 'di' is found, use the magnification formula m = -di/do, where 'm' is magnification. The minus sign indicates that the image is real and inverted if 'di' is positive. If 'm' is greater than 1, the image is larger than the object; if 'm' is less than 1, the image is smaller.

Note that without the specific focal length, we cannot proceed to numerical calculations.

Answer 2

To find the size of the image produced by a converging lens with a given focal length when an object is placed at a specific distance, you can use the thin-lens equation and the magnification formula. The magnification will tell you whether the image is larger or smaller than the actual size.

Step-by-step explanation:

To find the size of the image produced by a converging lens, we can use the thin-lens equation: 1/f = 1/do + 1/di, where f is the focal length of the lens, do is the object distance, and di is the image distance. In this case, the object is placed 34.0 cm behind the lens, so do = -34.0 cm (negative because the object is placed on the opposite side of the lens from the light source).

By substituting the known values into the equation and solving for di, we can find the image distance. Once we have the image distance, we can determine the size of the image using the magnification formula: m = -di/do.

The magnification will tell us whether the image is larger or smaller than the actual size. If the magnification is greater than 1, the image is larger than the actual size. If the magnification is less than 1, the image is smaller than the actual size. If the magnification is 1, the image is the same size as the actual object.