Question

Coulomb's law for the magnitude of the force F F between two particles with charges Q Q and Q′ Q ′ separated by a distance d d is |F|=K|QQ′|d2 | F | = K | Q Q ′ | d² , where K=14πϵ0 K = 1 /4 π ϵ 0 , and ϵ0=8.854×10⁻¹²C²/(N⋅m²) ϵ 0 = 8.854 × 10 ⁻¹² C ² / ( N ⋅ m²) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -15.5 nC n C , is located at x 1 = -1.700 m m ; the second charge, q2 = 31.5 nC n C , is at the origin (x = 0).

Answer 1

Coulomb's law calculates the magnitude of the force between two point charges. In this case, we need to find the distance between the charges and then use the equation to calculate the force.

Step-by-step explanation:

Coulomb's law calculates the magnitude of the force F between two point charges, Q and Q′, separated by a distance d. The formula is |F|=K|QQ′|/d², where K=1/(4πϵ₀), and ϵ₀=8.854×10⁻¹²C²/(N⋅m²) is the permittivity of free space.

In this given scenario, we have two charges located on the x-axis: q1 = -15.5 nC at x1 = -1.700 mm and q2 = 31.5 nC at x = 0. To calculate the force between these charges, we first need to find the distance between them, which is (x - x1).

By plugging in the known values, we can then calculate the magnitude of the force using Coulomb's law.