Question

Let X be a chi-squared random variable with 29 degrees of freedom. Find the following:(p(x) > 17.708)

(a)0.95
(b)0.90
(c)0.025
(d)0.05

Answer 1

We are given a chi-squared random variable X with 29 degrees of freedom and need to find the probability that the value of X is greater than 17.708 for different confidence levels.

Step-by-step explanation:

In this question, we are given a chi-squared random variable X with 29 degrees of freedom. We need to find the probability, p(x), that the value of X is greater than 17.708 for different confidence levels.

(a) For a 95% confidence level, the p-value will be 0.05. This means that there is a 0.05 probability of observing a chi-squared value greater than 17.708.

(b) For a 90% confidence level, the p-value will be 0.10. This means that there is a 0.10 probability of observing a chi-squared value greater than 17.708.

(c) For a 0.025 significance level, the p-value will be 0.025. This means that there is a 0.025 probability of observing a chi-squared value greater than 17.708.

(d) For a 0.05 significance level, the p-value will be 0.05. This means that there is a 0.05 probability of observing a chi-squared value greater than 17.708.