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When taking a 23 question multiple choice test, where each question has five possible answers, it would be unusual to get or more questions correct by guessing alone. Use the Range Rule of Thumb for Unusual Values to answer this question. Give your answer above as a whole number.

User Sniurkst
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Final answer:

Using the Range Rule of Thumb for Unusual Values, it would be unusual to guess more than 8 questions correctly on a 23 question multiple choice test with five possible answers each.

Step-by-step explanation:

To determine how unusual it is to get a certain number of questions correct by guessing on a multiple choice test, we can use the Range Rule of Thumb for Unusual Values. Given a 23-question test with five possible answers each, the expected number of correct answers by guessing alone is the product of the number of questions and the probability of guessing a question correctly, which is 1/5.

The expected number of correct answers is 23 * (1/5), which equals 4.6. To find the Range Rule of Thumb for Unusual Values, we calculate the standard deviation of a binomial distribution.

The standard deviation, σ, for a binomial distribution is calculated with the formula σ = √(np(1-p)), where n is the number of trials (23 questions), and p is the probability of success (1/5).

Plugging in the values, we get σ = √(23*(1/5)*(4/5)) = √(3.68) ≈ 1.92.

The Range Rule of Thumb states that values outside the range of (mean - 2*standard deviation, mean + 2*standard deviation) are considered unusual. Therefore, to find the range of usual values, we calculate:

  • Lower bound = Mean - 2*Standard Deviation = 4.6 - 2*1.92 = 0.76
  • Upper bound = Mean + 2*Standard Deviation = 4.6 + 2*1.92 = 8.44

Since we're interested in whole numbers of questions, we consider values outside the range of 1 to 8 as unusual.

To answer the initial question, it would be unusual for a student to guess more than 8 questions correctly on a 23 question test with 5 possible answers each.

User Whakkee
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