Question

Suppose the average client charge per hour for out-ofcourt work bylawyers in the state of Iowa is $125. Suppose further that a randomtelephone sample of 32 lawyers in Iowa is taken and that the sampleaverage charge per hour for out-of-court work is $110. If thepopulation variance is $525.

(A) what is the probability of getting a sample mean of $110 orlarger?
(B) What is the probability of getting a sample mean larger than$135 per hour?
(C) What is the probability of getting a sample mean of between$120 and $130 per hour?

Answer 1

To find the probability of getting a sample mean of $110 or larger, use the central limit theorem and standard normal distribution.

Step-by-step explanation:

To find the probability of getting a sample mean of $110 or larger, we can use the central limit theorem and the standard normal distribution.

1. Calculate the z-score for the sample mean using the formula: z = (sample mean - population mean) / (population standard deviation / sqrt(sample size))

2. Calculate the probability of getting a z-score of $110 or larger using a standard normal distribution table or a calculator.

For part (B) and (C), follow the same steps but substitute the sample mean values given in the question.