215k views
1 vote
Question 10 of 46 What are all possible values of x for which |x-2|<8?

User Walt D
by
8.1k points

1 Answer

3 votes

Final answer:

All possible values of x that satisfy the inequality |x-2|<8 are in the range of -6 < x < 10. This means x can be any number between -6 and 10, exclusive of the end points.

Step-by-step explanation:

The question asks for all possible values of x that satisfy the inequality |x-2| < 8. To solve this, we need to consider both the positive and negative scenarios that come from the absolute value.

Firstly, if x-2 is positive or zero, the absolute value has no effect, and the inequality stays the same:

  • x - 2 < 8

By adding 2 to both sides, we get:

  • x < 10

Secondly, if x-2 is negative, then the absolute value changes the sign:

  • -(x - 2) < 8 → -x + 2 < 8
  • Adding x to both sides gives us: 2 < 8 + x
  • Subtracting 8 from both sides gives us: -6 < x

Combining both scenarios, we have the inequality -6 < x < 10, which is the set of all values that x can take to satisfy the original inequality.

User Synchronizer
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.