Question

From a lot of 12 missiles, 5 are selected at random and fired Suppose the lot contains 3 defective missiles that will not fire (a) What is the probability that all 5 missiles will fire?

Answer 1

To find the probability that all 5 missiles will fire, we need to consider the number of favorable outcomes (missiles that will fire) and the total number of possible outcomes. In this case, there are 12 missiles in total and we want to select 5 of them. The probability that all 5 missiles will fire is the number of ways to select 5 out of 9 divided by the number of ways to select 5 out of 12. P(all 5 missiles will fire) = C(5,9) / C(5,12) = 84 / 792 = 0.106

Step-by-step explanation:

To find the probability that all 5 missiles will fire, we need to consider the number of favorable outcomes (missiles that will fire) and the total number of possible outcomes.

In this case, there are 12 missiles in total and we want to select 5 of them. Since 3 of the missiles are defective and will not fire, we have 9 missiles that will fire.

Therefore, the probability that all 5 missiles will fire is the number of ways to select 5 out of 9 divided by the number of ways to select 5 out of 12.

P(all 5 missiles will fire) = C(5,9) / C(5,12) = 84 / 792 = 0.106