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What is the mass of an object if it is attracted with a force of 0.2 N to another object of mass 7000 kg when the objects are 0.04 m apart

User Kodfire
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1 Answer

3 votes

Answer:

6.85 × 10² kg

Step-by-step explanation:

Given:

F = 0.2 N

m₁ = 7000 kg

d = 0.04 m


\boxed{F=(Gm_1m_2)/(d^2) }


0.2=(6.67*10^(-11)*7000* m_2)/(0.04^2)


2*10^(-1)=(6.67*10^(-11)*7*10^3* m_2)/((4*10^(-2))^2)


m_2=(2*10^(-1)*16*10^(-4))/(6.67*10^(-11)*7*10^(3))


=(2*16)/(6.67*7) *10^3


=6.85*10^2\ kg

User Atraudes
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7.5k points