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What is the slope-intercept form of the equation of the line containing the point (1,6) and having a slope of -2?

A) y = -2x + 13
B) y = -2x + 8
C) y = -2x + 4
D) y = -2x - 4

1 Answer

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Final answer:

The slope-intercept form of the equation of a line is y = mx + b. Plugging in the given values of the point (1,6) and the slope of -2, we can find the equation of the line through the point.

Step-by-step explanation:

The slope-intercept form of the equation of a line is given by y = mx + b, where m represents the slope and b represents the y-intercept.

Given a point (1,6) and a slope of -2, we can substitute these values into the slope-intercept form to find the equation of the line.

Plugging in the values, we have: y = -2x + b

Using the point (1,6), we can substitute the x and y values into the equation to solve for b.

When we substitute 1 for x and 6 for y, we get: 6 = -2(1) + b.

Simplifying the equation, we have: 6 = -2 + b. Solving for b, we get b = 8.

Therefore, the equation of the line is y = -2x + 8 (option B).

User Nick Frolov
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