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5 votes
How much greater, in dollars, is the median price than the mode of the prices listed?"

A) $3
B) $4
C) $5
D) $6

User Aye
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1 Answer

4 votes

Final answer:

To answer the student's question, first calculate the mode of the set of house prices as the most frequent value, which is $47,000. Then, find the median by averaging the two middle numbers of the ordered set, resulting in $49,250. The difference is $2,250, which doesn't match any of the provided options A) $3 B) $4 C) $5 D) $6, indicating a possible error in the options given.

Step-by-step explanation:

The student's question pertains to the comparison of the median and mode values of a given set of house prices. To solve this, we must first identify both the median and the mode. The mode is the most frequently occurring value. In the provided data set (45; 47; 47.5; 51; 53.5; 125), the only value that repeats is 47, so the mode is $47,000. To find the median, we list the values in order and find the center point. With an even number of data points, the median is the average of the middle two values. Thus, 47.5 and 51 are the two middle values, and the median is (47.5 + 51) / 2 = $49,250.

Now, subtract the mode from the median to determine the difference: $49,250 - $47,000 = $2,250. In this case, the given options A) $3 B) $4 C) $5 D) $6 seem to suggest there's a misunderstanding since none of the options match the calculated difference. Therefore, none of the provided options correctly answer the given question based on the house prices provided.

User Femotizo
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7.8k points