Question

Eric was so frustrated with his slow Chromebook that he threw it from his second-story window. The height in feet, h, of the laptop at the time in seconds, t, can be given by the following equation: h(t) = -16t^2 + 32t + 20. What is the height of the laptop 1 second after it is thrown?

A. h(1) = -16(1)² + 32(1) + 20
B. h(1) = -16(1)² + 32(1) - 20
C. h(1) = -16(1)² + 32(1) + 40
D. h(1) = -16(1)² + 32(1) - 40

Answer 1

The height of the laptop one second after Eric throws it from the second-story window is 36 feet, as calculated by the given quadratic equation h(t) = -16t^2 + 32t + 20.

Step-by-step explanation:

The height of the laptop 1 second after it is thrown is determined by substituting t = 1 second into the equation h(t) = -16t^2 + 32t + 20. Performing the calculations, we get:

h(1) = -16(1)² + 32(1) + 20

h(1) = -16(1) + 32 + 20

h(1) = -16 + 32 + 20

h(1) = 16 + 20

h(1) = 36 feet. So, the laptop is 36 feet above the ground after 1 second.