Question

Find the sum of the n terms of the arithmetic sequence.
4+6+8+…+62

Answer 1

The sum of the n terms of the arithmetic sequence 4+6+8+…+62 is 33n.

Step-by-step explanation:

The given arithmetic sequence is 4, 6, 8, ..., 62.

To find the sum of the n terms of an arithmetic sequence, we can use the formula: Sn = (n/2)(first term + last term), where Sn is the sum of the n terms.

Given that the first term (a) is 4 and the last term (l) is 62, we can substitute these values into the formula to find the sum:

Sn = (n/2)(a + l) = (n/2)(4 + 62) = (n/2)(66) = 33n