Final answer:
The HCF of the given terms 9abc, 3b²c, and abc² is 3bc.
Step-by-step explanation:
To find the HCF (Highest Common Factor) of the given terms, we first need to factorize each term. Let's factorize each term:
- 9abc = 3 * 3 * a * b * c
- 3b²c = 3 * b * b * c
- abc² = a * b * c * c
Now, we look for common factors among the terms. In this case, the common factors are 3, b, and c. So, the HCF of the given terms is 3 * b * c, which is equal to 3bc.