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A line passes through the point (-8,-1) and has a slope of (3)/(4). Write an equation in slope-intercept form for this line.

User Zhile Zou
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1 Answer

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Final answer:

The equation of the line is y = (3/4)x + 5.

Step-by-step explanation:

To write the equation of a line in slope-intercept form, we need the slope and the y-intercept. The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.

We know that the slope of the line is 3/4. substituting this into the slope-intercept form, we have y = (3/4)x + b. To determine the value of b, which is the y-intercept, we can substitute the coordinates of the given point (-8,-1) into the equation and solve for b.

-1 = (3/4)(-8) + b
-1 = -6 + b
b = -1 + 6
b = 5

So, the equation of the line in slope-intercept form is y = (3/4)x + 5.

User Ben Claar
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