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If JOSE is a rhombus with JO = 3x - 5 and OS = 13 cm, what is the perimeter of JOSE?

User Khatzie
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Final answer:

The perimeter of rhombus JOSE is 52 cm, calculated by solving the equation 3x - 5 = 13 to find the length of one side and then multiplying that length by 4.

Step-by-step explanation:

To find the perimeter of rhombus JOSE, we need to recognize that all sides of a rhombus are of equal length. Given that JO = 3x - 5 and an actual measurement of side OS is 13 cm, we can set 3x - 5 equal to 13 cm to solve for x:

3x - 5 = 13

3x = 13 + 5

3x = 18

x = 6

Now that we know x = 6, we can find the actual length of each side:

JO = 3(6) - 5

JO = 18 - 5

JO = 13 cm

Since all sides of a rhombus are equal, to find the perimeter (P), we multiply the length of one side by 4, because a rhombus has 4 sides:

P = 4 × side length

P = 4 × 13 cm

P = 52 cm

Therefore, the perimeter of rhombus JOSE is 52 cm.

User Manish Kothari
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