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Solve the quadratic equation: z² + 14z + 48 = 0.

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Final answer:

The solutions to the quadratic equation z² + 14z + 48 = 0 are found by factoring the equation into (z + 6)(z + 8) = 0 and solving for z, which gives z = -6 and z = -8.

Step-by-step explanation:

To solve the quadratic equation z² + 14z + 48 = 0, we can either factor the equation or use the quadratic formula. Since the equation factors easily, we can rewrite it as (z + 6)(z + 8) = 0. Setting each factor equal to zero, we find the two solutions for z:

  • z + 6 = 0 → z = -6
  • z + 8 = 0 → z = -8

Therefore, the solutions to the quadratic equation are z = -6 and z = -8.

User Krishnamoorthy
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