Question

What is the perimeter of a rectangle whose width is y and whose length is 2y-7 in simpliest form.

Answer 1

The perimeter of a rectangle with width y and length 2y-7 is 6y - 14, found by simplifying the expression 2y + 4y - 14.

Step-by-step explanation:

The perimeter of a rectangle is calculated by adding the lengths of all four sides. For a rectangle with width y and length 2y-7, we use the formula for the perimeter of a rectangle, which is 2 x (width + length). Plugging in the given values, we have:

Perimeter = 2 x (y + (2y - 7))

Now we simplify the expression:

Perimeter = 2y + 2(2y) - 2(7)

Perimeter = 2y + 4y - 14

Combining like terms, we get:

Perimeter = 6y - 14

Therefore, the perimeter of the rectangle in its simplest form is 6y - 14.