Question

In the accompanying diagram of circle O, diameter bar (AB) is perpendicular to chord bar (CD) and intersects bar (CD) at point E,AE=9, and EB=4. What is ED ?

Answer 1

In the given diagram, we have a circle with diameter AB and chord CD. We are given AE = 9 and EB = 4. To find ED, we need to find the length of chord CD. Since AB is perpendicular to CD and passes through the center of the circle, it bisects CD, making CE = DE. Therefore, ED is equal to 5.

Step-by-step explanation:

In the given diagram, we have a circle with diameter AB and chord CD. Diameter AB intersects chord CD at point E. We are given that AE = 9 and EB = 4. To find ED, we need to find the length of chord CD.

Since AB is perpendicular to CD and passes through the center of the circle, it bisects CD. Therefore, CE = DE. Since AE = 9 and EB = 4, we can subtract EB from AE to find CE = 9 - 4 = 5. Since CE = DE, ED is also equal to 5.