75.8k views
0 votes
Given parallelogram PQRS with diagonals PR and QS intersect at T. If PT=24 and PR=2x-10 find the value of x.

User Ardavan
by
7.8k points

1 Answer

3 votes

Final answer:

By using the property that diagonals of a parallelogram bisect each other, the equation 2x - 10 for diagonal PR can be solved given PT is 24 by setting PT equal to TR and solving for x, which is found to be 29.

Step-by-step explanation:

In the context of a parallelogram PQRS with diagonals PR and QS intersecting at T, the property states that diagonals of a parallelogram bisect each other. Thus, PT equals TR. Given that PT is 24 units and the entire diagonal PR is represented by the equation 2x-10, we can set up the equation:

PT + TR = PR

24 + 24 = 2x - 10

48 = 2x - 10

Now we can add 10 to both sides to isolate the term with x on one side of the equation, and then divide by 2 to solve for x:

58 = 2x

x = 29

User Joshua Welz
by
7.8k points