Final answer:
Line AC is congruent to BD because triangle ACB and triangle ADB are congruent by the SAS (Side-Angle-Side) congruence postulate.
Step-by-step explanation:
Given that line AB is a diameter of circle O and that AC is parallel to BD, we can conclude that line AC is congruent to BD.
Since AB is a diameter of the circle, it passes through the center of the circle. This means that triangle ACB and triangle ADB are congruent by the SAS (Side-Angle-Side) congruence postulate.
Since corresponding sides of congruent triangles are congruent, we can conclude that AC is congruent to BD.