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Find P(A cap B) if events A and B are independent and P(A)=0.4 and P(B)=0.7 and Find P(A cup B) if events A and B are mutually exclusive and P(A)"

User Orel Eraki
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Final answer:

To find P(A ∩ B) when A and B are independent, multiply P(A) by P(B), resulting in 0.28. For mutually exclusive events A and B, P(A ∪ B) is the sum of P(A) and P(B), but it cannot be calculated without the value of P(B).

Step-by-step explanation:

Finding P(A ∩ B) for Independent Events

When events A and B are independent, the probability of both events occurring simultaneously, represented by P(A ∩ B), is the product of their individual probabilities. Given that P(A)=0.4 and P(B)=0.7, calculating P(A ∩ B) for independent events is as follows:

P(A ∩ B) = P(A) × P(B) = 0.4 × 0.7 = 0.28.

Finding P(A ∪ B) for Mutually Exclusive Events

If events A and B are mutually exclusive, they cannot occur at the same time, which means P(A ∩ B) = 0. The probability of either A or B occurring, P(A ∪ B), is the sum of their individual probabilities. However, since P(B) is not provided in the question, we cannot calculate P(A ∪ B). Thus, we would need P(B) to compute:

P(A ∪ B) = P(A) + P(B).

User Cafertayyar
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