161k views
0 votes
In triangle ABC, where angle A = 45 degrees, AB = 20, and AC = 15, what is the length of BC to the nearest tenth?

User Chsword
by
7.7k points

1 Answer

2 votes

Final answer:

To find the length of BC in triangle ABC with angle A at 45 degrees, side AB at 20, and side AC at 15, we use the law of cosines and round the result to the nearest tenth.

Step-by-step explanation:

To find the length of BC in triangle ABC where angle A is 45 degrees, AB is 20, and AC is 15, we can use the law of cosines. Since triangle ABC is not a right triangle we cannot directly apply the Pythagorean theorem, but instead, we must apply the law of cosines:

BC² = AB² + AC² - 2(AB)(AC)cos(A)

Plugging in the values:

BC² = 20² + 15² - 2(20)(15)cos(45°)

BC² = 400 + 225 - 600(cos(45°))

Since cos(45°) = √2/2,

BC² = 625 - 600(√2/2)

BC² = 625 - 300√2

BC = √(625 - 300√2)

Calculating the radical expression gives us the length of BC. After performing this calculation, we round the result to the nearest tenth to obtain the final answer.

User TechDog
by
9.0k points