Final answer:
To find the equation of the line passing through the points (-6, -4) and (-3, 2), calculate the slope as 2, then use the point-slope form to derive the slope-intercept form of the equation: y = 2x + 8.
Step-by-step explanation:
To find the equation of the line passing through the points (-6, -4) and (-3, 2), we first need to calculate the slope (m) of the line using the formula:
m = (Y2 - Y1) / (X2 - X1)
For our points, (-6, -4) and (-3, 2), we designate (-6, -4) as (X1, Y1) and (-3, 2) as (X2, Y2).
Therefore, m = (2 - (-4)) / (-3 - (-6)) = 6 / 3 = 2.
Now, we will use the slope and one of the points to find the equation in the point-slope form, y - Y1 = m(x - X1).
For the point (-6, -4): y - (-4) = 2(x - (-6))
y + 4 = 2x + 12
To find the slope-intercept form, we simplify this to y = 2x + 8.
The equation of the line passing through the points (-6, -4) and (-3, 2) is y = 2x + 8.