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Find the equation of the line passing through the points (-6, -4) and (-3, 2).

User RmLuma
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Final answer:

To find the equation of the line passing through the points (-6, -4) and (-3, 2), calculate the slope as 2, then use the point-slope form to derive the slope-intercept form of the equation: y = 2x + 8.

Step-by-step explanation:

To find the equation of the line passing through the points (-6, -4) and (-3, 2), we first need to calculate the slope (m) of the line using the formula:

m = (Y2 - Y1) / (X2 - X1)

For our points, (-6, -4) and (-3, 2), we designate (-6, -4) as (X1, Y1) and (-3, 2) as (X2, Y2).

Therefore, m = (2 - (-4)) / (-3 - (-6)) = 6 / 3 = 2.

Now, we will use the slope and one of the points to find the equation in the point-slope form, y - Y1 = m(x - X1).

For the point (-6, -4): y - (-4) = 2(x - (-6))

y + 4 = 2x + 12

To find the slope-intercept form, we simplify this to y = 2x + 8.

The equation of the line passing through the points (-6, -4) and (-3, 2) is y = 2x + 8.

User LightningWar
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