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Consider the system of inequalities given below.

y≤ 2x+20
y≤ 1.2x+7.2
y≥ 0
x≥ 0
This feasible region is bounded Its corner points are _________

User Yuuuu
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1 Answer

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Final answer:

The corner points of the feasible region are (0, 0) and (15, 18).

Step-by-step explanation:

The system of inequalities given is:

y ≤ 2x+20

y ≤ 1.2x+7.2

y ≥ 0

x ≥ 0

To find the corner points of the feasible region, we need to solve the system of equations formed by each pair of lines that intersect. The corner points are the intersection points of the lines.

By solving the system of equations formed by the first two inequalities, we get the intersection point (x, y) = (0, 0).

Similarly, by solving the system of equations formed by the first and third inequalities, we get the intersection point (x, y) = (0, 0).

Finally, by solving the system of equations formed by the second and third inequalities, we get the intersection point (x, y) = (15, 18).

Therefore, the corner points of the feasible region are (0, 0) and (15, 18).

User Vladimir K
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