Final answer:
The equation of the line that passes through (-4, -4) and is parallel to y = (7/4)x - 1 is y = (7/4)x + 3.
Step-by-step explanation:
The student is asking for help with a mathematics problem involving finding the equation of a line. The line needs to pass through a given point (-4, -4) and be parallel to a given line, y = (7/4)x - 1. To be parallel to the given line, the new line must have the same slope, which is 7/4. Hence, the equation of the line can be found using the point-slope form, which is y - y1 = m(x - x1), where (x1, y1) is the point the line passes through, and m is the slope.
Following this formula, the equation for the new line is y - (-4) = (7/4)(x - (-4)), which simplifies to y + 4 = (7/4)x + 7. After subtracting 4 from both sides, the final equation of the line is y = (7/4)x + 3.