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What is the diameter of the circle (x-(22)/(3))^(2)+(y+(28)/(3))^(2)=58?

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Final answer:

The diameter of the circle is 2√58.

Step-by-step explanation:

The equation given represents a circle in the form (x-h)2+(y-k)2=r2, where (h,k) is the center of the circle and r is the radius. By comparing the given equation to this form, we can find the center of the circle. In this case, the center is at (h,k) = (22/3,-28/3). The radius, r, can be found by taking the square root of the constant term. So, r = √58. The diameter of the circle is twice the radius, so the diameter is 2√58.

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