105k views
2 votes
Write the general form of the circle g x^(2)+y^(2)+2x+18y+57=0

1 Answer

6 votes

Final answer:

The general form of the circle g x^2 + y^2 + 2x + 18y + 57 = 0 is x^2 + y^2 + 2ax + 2by + c = 0, where the coordinates of the center and the radius can be determined from the coefficients in the equation. In this specific equation, the circle has a radius of sqrt(-47), which is an imaginary number.

Step-by-step explanation:

The general form of a circle is represented by the equation x2 + y2 + 2ax + 2by + c = 0, where the center of the circle is (-a, -b) and the radius is √(a2 + b2 - c).

In this specific equation, g x2 + y2 + 2x + 18y + 57 = 0, we can identify that a = 1, b = 9, and c = 57. Therefore, the center of the circle is (-1, -9) and the radius is √(1 + 9 - 57) = √-47, which is an imaginary number. This means that the circle does not intersect the x-axis or the y-axis and there are no real points on the circle.

User Kalpa
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories