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Triangle ABC has sides a=53, b=60 and c=72. find area ?

User Teqnology
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Final answer:

To find the area of triangle ABC with sides a = 53, b = 60, and c = 72, we can use Heron's formula. The area is approximately 594.73 square units.

Step-by-step explanation:

To find the area of triangle ABC, we can use Heron's formula. Heron's formula states that the area of a triangle with sides a, b, and c is given by:

Area = sqrt(s(s-a)(s-b)(s-c))

where s is the semi-perimeter of the triangle, which is calculated as:

s = (a + b + c) / 2

For the given triangle ABC with sides a = 53, b = 60, and c = 72, we can substitute the values into the formula to find the area:

Area = sqrt(63(63-53)(63-60)(63-72))

Area ≈ 594.73 square units

User Empiric
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