Final answer:
The student asked to calculate the total kinetic energy for a moving motorcycle, which involves calculating its translational kinetic energy since no angular velocity was given for the wheels. Using the mass of the motorcycle and its speed, the translational kinetic energy is found to be 150,070 J. The rotational kinetic energy cannot be calculated without the angular velocity.
Step-by-step explanation:
The student has asked to calculate the total kinetic energy of a 220 kg motorcycle moving at a speed of 37 m/s, considering the rotational kinetic energy of its wheels. The wheels are each annular rings with an inner radius of 0.280 m and an outer radius of 0.350 m, weighing 12 kg each. To find the total kinetic energy, we need to calculate both the translational and rotational kinetic energy of the motorcycle and its wheels.
Firstly, the translational kinetic energy (TKE) of the motorcycle can be calculated using the formula:
TKE = (1/2) * m * v^2,
where m represents the mass of the motorcycle, and v is its velocity. For the rotational kinetic energy (RKE) of the wheels, we can use the formula for the kinetic energy of a rotating annular ring:
RKE = (1/2) * I * ω^2,
where I is the moment of inertia of an annular ring, which is I = (1/2) * M * (R1^2 + R2^2), and ω is the angular velocity. However, since no angular velocity is provided in the original question, we'll only focus on the total kinetic energy due to translational motion in this case.
Calculating the translational kinetic energy:
TKE = (1/2) * 220 kg * (37 m/s)^2
TKE = 150,070 J
The motorcycle's wheels contribute to the total kinetic energy through their rotation, yet without the angular velocity, that part of the calculation is impossible in this scenario. Therefore, the answer provided is solely the translational kinetic energy of the motorcycle, and we assume that the wheels are not spinning, or this value is in addition to the rotational kinetic energy if the wheels were spinning.